Base | Representation |
---|---|
bin | 1110101011111101110… |
… | …1100111011100001011 |
3 | 220010021122012002010022 |
4 | 3222333131213130023 |
5 | 13113223000041042 |
6 | 311525300011055 |
7 | 24141506201645 |
oct | 3527735473413 |
9 | 803248162108 |
10 | 252320315147 |
11 | 9801027037a |
12 | 40a99690a8b |
13 | 1aa419c7a34 |
14 | c2d8a4b895 |
15 | 686b89ecd2 |
hex | 3abf76770b |
252320315147 has 2 divisors, whose sum is σ = 252320315148. Its totient is φ = 252320315146.
The previous prime is 252320315119. The next prime is 252320315179. The reversal of 252320315147 is 741513023252.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 252320315147 - 26 = 252320315083 is a prime.
It is not a weakly prime, because it can be changed into another prime (252320318147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126160157573 + 126160157574.
It is an arithmetic number, because the mean of its divisors is an integer number (126160157574).
Almost surely, 2252320315147 is an apocalyptic number.
252320315147 is a deficient number, since it is larger than the sum of its proper divisors (1).
252320315147 is an equidigital number, since it uses as much as digits as its factorization.
252320315147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 35.
Adding to 252320315147 its reverse (741513023252), we get a palindrome (993833338399).
The spelling of 252320315147 in words is "two hundred fifty-two billion, three hundred twenty million, three hundred fifteen thousand, one hundred forty-seven".
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