Base | Representation |
---|---|
bin | 1110101100000011010… |
… | …1101011011100010011 |
3 | 220010100020121220212200 |
4 | 3223000311223130103 |
5 | 13113244402301321 |
6 | 311531442454243 |
7 | 24142206340230 |
oct | 3530065533423 |
9 | 803306556780 |
10 | 252343400211 |
11 | 980222a8541 |
12 | 40aa5364383 |
13 | 1aa4671b436 |
14 | c2dbb3a787 |
15 | 686d90ed26 |
hex | 3ac0d6b713 |
252343400211 has 96 divisors (see below), whose sum is σ = 438328450560. Its totient is φ = 136847273472.
The previous prime is 252343400201. The next prime is 252343400213. The reversal of 252343400211 is 112004343252.
252343400211 is a `hidden beast` number, since 2 + 5 + 2 + 3 + 43 + 400 + 211 = 666.
It is not a de Polignac number, because 252343400211 - 26 = 252343400147 is a prime.
It is not an unprimeable number, because it can be changed into a prime (252343400213) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 40941816 + ... + 40947978.
It is an arithmetic number, because the mean of its divisors is an integer number (4565921360).
Almost surely, 2252343400211 is an apocalyptic number.
252343400211 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
252343400211 is a deficient number, since it is larger than the sum of its proper divisors (185985050349).
252343400211 is a wasteful number, since it uses less digits than its factorization.
252343400211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6585 (or 6582 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 252343400211 its reverse (112004343252), we get a palindrome (364347743463).
The spelling of 252343400211 in words is "two hundred fifty-two billion, three hundred forty-three million, four hundred thousand, two hundred eleven".
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