2525252031433 has 2 divisors, whose sum is σ = 2525252031434. Its totient is φ = 2525252031432.

The previous prime is 2525252031371. The next prime is 2525252031473. The reversal of 2525252031433 is 3341302525252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2281800576969 + 243451454464 = 1510563^2 + 493408^2 .

It is a cyclic number.

It is not a de Polignac number, because 2525252031433 - 2²¹ = 2525249934281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2525252031392 and 2525252031401.

It is not a weakly prime, because it can be changed into another prime (2525252031473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1262626015716 + 1262626015717.

It is an arithmetic number, because the mean of its divisors is an integer number (1262626015717).

Almost surely, 2^{2525252031433} is an apocalyptic number.

It is an amenable number.

2525252031433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2525252031433 is an equidigital number, since it uses as much as digits as its factorization.

2525252031433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 37.

Adding to 2525252031433 its reverse (3341302525252), we get a palindrome (5866554556685).

The spelling of 2525252031433 in words is "two trillion, five hundred twenty-five billion, two hundred fifty-two million, thirty-one thousand, four hundred thirty-three".