Base | Representation |
---|---|
bin | 100100101111111010101… |
… | …010001000011010001001 |
3 | 22221102101001201110222001 |
4 | 210233322222020122021 |
5 | 312333404343314431 |
6 | 5212044051231001 |
7 | 350310361416352 |
oct | 44577252103211 |
9 | 8842331643861 |
10 | 2525351151241 |
11 | 893aa4986446 |
12 | 34951aba8461 |
13 | 1541a78b5849 |
14 | 8a328946d29 |
15 | 45a54547e61 |
hex | 24bfaa88689 |
2525351151241 has 2 divisors, whose sum is σ = 2525351151242. Its totient is φ = 2525351151240.
The previous prime is 2525351151217. The next prime is 2525351151299. The reversal of 2525351151241 is 1421511535252.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1823742211600 + 701608939641 = 1350460^2 + 837621^2 .
It is a cyclic number.
It is not a de Polignac number, because 2525351151241 - 211 = 2525351149193 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2525351151241.
It is not a weakly prime, because it can be changed into another prime (2525351151541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1262675575620 + 1262675575621.
It is an arithmetic number, because the mean of its divisors is an integer number (1262675575621).
Almost surely, 22525351151241 is an apocalyptic number.
It is an amenable number.
2525351151241 is a deficient number, since it is larger than the sum of its proper divisors (1).
2525351151241 is an equidigital number, since it uses as much as digits as its factorization.
2525351151241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 60000, while the sum is 37.
Adding to 2525351151241 its reverse (1421511535252), we get a palindrome (3946862686493).
The spelling of 2525351151241 in words is "two trillion, five hundred twenty-five billion, three hundred fifty-one million, one hundred fifty-one thousand, two hundred forty-one".
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