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2525351151241 is a prime number
BaseRepresentation
bin100100101111111010101…
…010001000011010001001
322221102101001201110222001
4210233322222020122021
5312333404343314431
65212044051231001
7350310361416352
oct44577252103211
98842331643861
102525351151241
11893aa4986446
1234951aba8461
131541a78b5849
148a328946d29
1545a54547e61
hex24bfaa88689

2525351151241 has 2 divisors, whose sum is σ = 2525351151242. Its totient is φ = 2525351151240.

The previous prime is 2525351151217. The next prime is 2525351151299. The reversal of 2525351151241 is 1421511535252.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1823742211600 + 701608939641 = 1350460^2 + 837621^2 .

It is a cyclic number.

It is not a de Polignac number, because 2525351151241 - 211 = 2525351149193 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2525351151241.

It is not a weakly prime, because it can be changed into another prime (2525351151541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1262675575620 + 1262675575621.

It is an arithmetic number, because the mean of its divisors is an integer number (1262675575621).

Almost surely, 22525351151241 is an apocalyptic number.

It is an amenable number.

2525351151241 is a deficient number, since it is larger than the sum of its proper divisors (1).

2525351151241 is an equidigital number, since it uses as much as digits as its factorization.

2525351151241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60000, while the sum is 37.

Adding to 2525351151241 its reverse (1421511535252), we get a palindrome (3946862686493).

The spelling of 2525351151241 in words is "two trillion, five hundred twenty-five billion, three hundred fifty-one million, one hundred fifty-one thousand, two hundred forty-one".