Base | Representation |
---|---|
bin | 1011011111000001110100… |
… | …11110100001100110011001 |
3 | 10022102101120110121220221221 |
4 | 11233200322132201212121 |
5 | 11302241014011442303 |
6 | 125414055422332041 |
7 | 5214433035425332 |
oct | 557407236414631 |
9 | 108371513556857 |
10 | 25255388780953 |
11 | 8057828618721 |
12 | 29ba7b672a021 |
13 | 111275a9a9666 |
14 | 63451dd9b289 |
15 | 2dbe3d5224bd |
hex | 16f83a7a1999 |
25255388780953 has 2 divisors, whose sum is σ = 25255388780954. Its totient is φ = 25255388780952.
The previous prime is 25255388780929. The next prime is 25255388781019. The reversal of 25255388780953 is 35908788355252.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25146744710409 + 108644070544 = 5014653^2 + 329612^2 .
It is a cyclic number.
It is not a de Polignac number, because 25255388780953 - 29 = 25255388780441 is a prime.
It is not a weakly prime, because it can be changed into another prime (25255388780353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12627694390476 + 12627694390477.
It is an arithmetic number, because the mean of its divisors is an integer number (12627694390477).
Almost surely, 225255388780953 is an apocalyptic number.
It is an amenable number.
25255388780953 is a deficient number, since it is larger than the sum of its proper divisors (1).
25255388780953 is an equidigital number, since it uses as much as digits as its factorization.
25255388780953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760000, while the sum is 70.
The spelling of 25255388780953 in words is "twenty-five trillion, two hundred fifty-five billion, three hundred eighty-eight million, seven hundred eighty thousand, nine hundred fifty-three".
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