Search a number
-
+
25261240441 = 73313445811
BaseRepresentation
bin10111100001101011…
…111111000001111001
32102012111110222022211
4113201223333001321
5403213334143231
615334352015121
71552666000213
oct274153770171
972174428284
1025261240441
11a793347918
124a8bb314a1
1324c76b3268
141318d4b5b3
159ccac6eb1
hex5e1aff079

25261240441 has 4 divisors (see below), whose sum is σ = 25264693584. Its totient is φ = 25257787300.

The previous prime is 25261240439. The next prime is 25261240451. The reversal of 25261240441 is 14404216252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25261240441 - 21 = 25261240439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25261240451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1715575 + ... + 1730236.

It is an arithmetic number, because the mean of its divisors is an integer number (6316173396).

Almost surely, 225261240441 is an apocalyptic number.

It is an amenable number.

25261240441 is a deficient number, since it is larger than the sum of its proper divisors (3453143).

25261240441 is an equidigital number, since it uses as much as digits as its factorization.

25261240441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3453142.

The product of its (nonzero) digits is 15360, while the sum is 31.

Adding to 25261240441 its reverse (14404216252), we get a palindrome (39665456693).

The spelling of 25261240441 in words is "twenty-five billion, two hundred sixty-one million, two hundred forty thousand, four hundred forty-one".

Divisors: 1 7331 3445811 25261240441