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25275807937 is a prime number
BaseRepresentation
bin10111100010100011…
…100011100011000001
32102020111220002011201
4113202203203203001
5403231101323222
615340032141201
71553233552102
oct274243434301
972214802151
1025275807937
11a7a0597676
124a94997801
1324ca713a93
14131ac603a9
159ce003427
hex5e28e38c1

25275807937 has 2 divisors, whose sum is σ = 25275807938. Its totient is φ = 25275807936.

The previous prime is 25275807913. The next prime is 25275808009. The reversal of 25275807937 is 73970857252.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25027556401 + 248251536 = 158201^2 + 15756^2 .

It is a cyclic number.

It is not a de Polignac number, because 25275807937 - 215 = 25275775169 is a prime.

It is a super-3 number, since 3×252758079373 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (25275807737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12637903968 + 12637903969.

It is an arithmetic number, because the mean of its divisors is an integer number (12637903969).

Almost surely, 225275807937 is an apocalyptic number.

It is an amenable number.

25275807937 is a deficient number, since it is larger than the sum of its proper divisors (1).

25275807937 is an equidigital number, since it uses as much as digits as its factorization.

25275807937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7408800, while the sum is 55.

The spelling of 25275807937 in words is "twenty-five billion, two hundred seventy-five million, eight hundred seven thousand, nine hundred thirty-seven".