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2529134057 is a prime number
BaseRepresentation
bin1001011010111111…
…1000010111101001
320112021000022200202
42112233320113221
520134424242212
61054544041545
7116450166452
oct22657702751
96467008622
102529134057
1110886a293a
125a70032b5
13313c90238
1419dc76129
15ec0830c2
hex96bf85e9

2529134057 has 2 divisors, whose sum is σ = 2529134058. Its totient is φ = 2529134056.

The previous prime is 2529134033. The next prime is 2529134071. The reversal of 2529134057 is 7504319252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2346046096 + 183087961 = 48436^2 + 13531^2 .

It is a cyclic number.

It is not a de Polignac number, because 2529134057 - 212 = 2529129961 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2529134057.

It is not a weakly prime, because it can be changed into another prime (2529134017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1264567028 + 1264567029.

It is an arithmetic number, because the mean of its divisors is an integer number (1264567029).

Almost surely, 22529134057 is an apocalyptic number.

It is an amenable number.

2529134057 is a deficient number, since it is larger than the sum of its proper divisors (1).

2529134057 is an equidigital number, since it uses as much as digits as its factorization.

2529134057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 38.

The square root of 2529134057 is about 50290.4966867499. The cubic root of 2529134057 is about 1362.4605932210.

The spelling of 2529134057 in words is "two billion, five hundred twenty-nine million, one hundred thirty-four thousand, fifty-seven".