253001628433 has 4 divisors (see below), whose sum is σ = 254272993600. Its totient is φ = 251730263268.

The previous prime is 253001628431. The next prime is 253001628449. The reversal of 253001628433 is 334826100352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 253001628433 - 2¹ = 253001628431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 253001628392 and 253001628401.

It is not an unprimeable number, because it can be changed into a prime (253001628431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 635682285 + ... + 635682682.

It is an arithmetic number, because the mean of its divisors is an integer number (63568248400).

Almost surely, 2^253001628433 is an apocalyptic number.

It is an amenable number.

253001628433 is a deficient number, since it is larger than the sum of its proper divisors (1271365167).

253001628433 is a wasteful number, since it uses less digits than its factorization.

253001628433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1271365166.

The product of its (nonzero) digits is 103680, while the sum is 37.

Adding to 253001628433 its reverse (334826100352), we get a palindrome (587827728785).

The spelling of 253001628433 in words is "two hundred fifty-three billion, one million, six hundred twenty-eight thousand, four hundred thirty-three".