Base | Representation |
---|---|
bin | 1011100000010101011001… |
… | …00110001001101001110001 |
3 | 10022120200101010200012211201 |
4 | 11300022230212021221301 |
5 | 11304004404240234401 |
6 | 125450435323411201 |
7 | 5220611566446016 |
oct | 560125446115161 |
9 | 108520333605751 |
10 | 25300253055601 |
11 | 8074860301257 |
12 | 2a07437683b01 |
13 | 1116a5a749034 |
14 | 6367785b970d |
15 | 2dd1b70a0b01 |
hex | 1702ac989a71 |
25300253055601 has 2 divisors, whose sum is σ = 25300253055602. Its totient is φ = 25300253055600.
The previous prime is 25300253055527. The next prime is 25300253055619. The reversal of 25300253055601 is 10655035200352.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23290266348001 + 2009986707600 = 4825999^2 + 1417740^2 .
It is a cyclic number.
It is not a de Polignac number, because 25300253055601 - 215 = 25300253022833 is a prime.
It is not a weakly prime, because it can be changed into another prime (25300253055001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12650126527800 + 12650126527801.
It is an arithmetic number, because the mean of its divisors is an integer number (12650126527801).
Almost surely, 225300253055601 is an apocalyptic number.
It is an amenable number.
25300253055601 is a deficient number, since it is larger than the sum of its proper divisors (1).
25300253055601 is an equidigital number, since it uses as much as digits as its factorization.
25300253055601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135000, while the sum is 37.
Adding to 25300253055601 its reverse (10655035200352), we get a palindrome (35955288255953).
The spelling of 25300253055601 in words is "twenty-five trillion, three hundred billion, two hundred fifty-three million, fifty-five thousand, six hundred one".
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