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25300253055601 is a prime number
BaseRepresentation
bin1011100000010101011001…
…00110001001101001110001
310022120200101010200012211201
411300022230212021221301
511304004404240234401
6125450435323411201
75220611566446016
oct560125446115161
9108520333605751
1025300253055601
118074860301257
122a07437683b01
131116a5a749034
146367785b970d
152dd1b70a0b01
hex1702ac989a71

25300253055601 has 2 divisors, whose sum is σ = 25300253055602. Its totient is φ = 25300253055600.

The previous prime is 25300253055527. The next prime is 25300253055619. The reversal of 25300253055601 is 10655035200352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23290266348001 + 2009986707600 = 4825999^2 + 1417740^2 .

It is a cyclic number.

It is not a de Polignac number, because 25300253055601 - 215 = 25300253022833 is a prime.

It is not a weakly prime, because it can be changed into another prime (25300253055001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12650126527800 + 12650126527801.

It is an arithmetic number, because the mean of its divisors is an integer number (12650126527801).

Almost surely, 225300253055601 is an apocalyptic number.

It is an amenable number.

25300253055601 is a deficient number, since it is larger than the sum of its proper divisors (1).

25300253055601 is an equidigital number, since it uses as much as digits as its factorization.

25300253055601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135000, while the sum is 37.

Adding to 25300253055601 its reverse (10655035200352), we get a palindrome (35955288255953).

The spelling of 25300253055601 in words is "twenty-five trillion, three hundred billion, two hundred fifty-three million, fifty-five thousand, six hundred one".