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2530444344013 = 15157135838191
BaseRepresentation
bin100100110100101010001…
…111000111101011001101
322221220112000110110222101
4210310222033013223031
5312424322223002023
65214245312115101
7350550525015025
oct44645217075315
98856460413871
102530444344013
11896178955573
1234a500835a91
13154809b43691
148a68d146a85
1545c5175c1ad
hex24d2a3c7acd

2530444344013 has 16 divisors (see below), whose sum is σ = 2552686968832. Its totient is φ = 2508277590000.

The previous prime is 2530444344011. The next prime is 2530444344041. The reversal of 2530444344013 is 3104434440352.

It is a cyclic number.

It is not a de Polignac number, because 2530444344013 - 21 = 2530444344011 is a prime.

It is a super-3 number, since 3×25304443440133 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2530444344011) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 308925748 + ... + 308933938.

It is an arithmetic number, because the mean of its divisors is an integer number (159542935552).

Almost surely, 22530444344013 is an apocalyptic number.

It is an amenable number.

2530444344013 is a deficient number, since it is larger than the sum of its proper divisors (22242624819).

2530444344013 is a wasteful number, since it uses less digits than its factorization.

2530444344013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12496.

The product of its (nonzero) digits is 276480, while the sum is 37.

Adding to 2530444344013 its reverse (3104434440352), we get a palindrome (5634878784365).

The spelling of 2530444344013 in words is "two trillion, five hundred thirty billion, four hundred forty-four million, three hundred forty-four thousand, thirteen".

Divisors: 1 151 571 3583 8191 86221 541033 1236841 2045893 4677061 29348353 308929843 706236211 4431601303 16757909563 2530444344013