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25305414137 is a prime number
BaseRepresentation
bin10111100100010100…
…011111100111111001
32102022120121020020122
4113210110133213321
5403311141223022
615343010503025
71554043320413
oct274424374771
972276536218
1025305414137
11a806279203
124aa2894a75
1325038ab743
141320b699b3
159d1900742
hex5e451f9f9

25305414137 has 2 divisors, whose sum is σ = 25305414138. Its totient is φ = 25305414136.

The previous prime is 25305414109. The next prime is 25305414161. The reversal of 25305414137 is 73141450352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24140147641 + 1165266496 = 155371^2 + 34136^2 .

It is a cyclic number.

It is not a de Polignac number, because 25305414137 - 212 = 25305410041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25305414097 and 25305414106.

It is not a weakly prime, because it can be changed into another prime (25305414187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12652707068 + 12652707069.

It is an arithmetic number, because the mean of its divisors is an integer number (12652707069).

Almost surely, 225305414137 is an apocalyptic number.

It is an amenable number.

25305414137 is a deficient number, since it is larger than the sum of its proper divisors (1).

25305414137 is an equidigital number, since it uses as much as digits as its factorization.

25305414137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 35.

Adding to 25305414137 its reverse (73141450352), we get a palindrome (98446864489).

The spelling of 25305414137 in words is "twenty-five billion, three hundred five million, four hundred fourteen thousand, one hundred thirty-seven".