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2530892776931 is a prime number
BaseRepresentation
bin100100110101000100111…
…101110000010111100011
322221221200021021020021222
4210311010331300113203
5312431232022330211
65214402011405255
7350564611436441
oct44650475602743
98857607236258
102530892776931
11896388aa0892
1234a606a5382b
1315487ba11cbc
148a6d2917b91
1545c7acdb1db
hex24d44f705e3

2530892776931 has 2 divisors, whose sum is σ = 2530892776932. Its totient is φ = 2530892776930.

The previous prime is 2530892776913. The next prime is 2530892776991. The reversal of 2530892776931 is 1396772980352.

2530892776931 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (2530892776913) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2530892776931 - 210 = 2530892775907 is a prime.

It is a super-3 number, since 3×25308927769313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (2530892776991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265446388465 + 1265446388466.

It is an arithmetic number, because the mean of its divisors is an integer number (1265446388466).

Almost surely, 22530892776931 is an apocalyptic number.

2530892776931 is a deficient number, since it is larger than the sum of its proper divisors (1).

2530892776931 is an equidigital number, since it uses as much as digits as its factorization.

2530892776931 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34292160, while the sum is 62.

The spelling of 2530892776931 in words is "two trillion, five hundred thirty billion, eight hundred ninety-two million, seven hundred seventy-six thousand, nine hundred thirty-one".