Base | Representation |
---|---|
bin | 111001100100010001000100… |
… | …011011101110110111001011 |
3 | 1020012102212002212020010121001 |
4 | 321210101010123232313023 |
5 | 231141103420323111011 |
6 | 2254245405110355431 |
7 | 104220500143251061 |
oct | 7144210433566713 |
9 | 1205385085203531 |
10 | 253180880285131 |
11 | 73742454566567 |
12 | 2449019865bb77 |
13 | ab36b15639266 |
14 | 467403cbc8031 |
15 | 1e40c380817c1 |
hex | e644446eedcb |
253180880285131 has 2 divisors, whose sum is σ = 253180880285132. Its totient is φ = 253180880285130.
The previous prime is 253180880285033. The next prime is 253180880285189. The reversal of 253180880285131 is 131582088081352.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 253180880285131 - 211 = 253180880283083 is a prime.
It is a super-3 number, since 3×2531808802851313 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (253180880285191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126590440142565 + 126590440142566.
It is an arithmetic number, because the mean of its divisors is an integer number (126590440142566).
Almost surely, 2253180880285131 is an apocalyptic number.
253180880285131 is a deficient number, since it is larger than the sum of its proper divisors (1).
253180880285131 is an equidigital number, since it uses as much as digits as its factorization.
253180880285131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3686400, while the sum is 55.
The spelling of 253180880285131 in words is "two hundred fifty-three trillion, one hundred eighty billion, eight hundred eighty million, two hundred eighty-five thousand, one hundred thirty-one".
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