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253243314097 is a prime number
BaseRepresentation
bin1110101111011001111…
…0100100111110110001
3220012122221222021122121
43223312132210332301
513122120242022342
6312201031034241
724203414436664
oct3536636447661
9805587867577
10253243314097
1198444281124
12410b680b981
131ab5acb4867
14c3854736db
1568c2921067
hex3af67a4fb1

253243314097 has 2 divisors, whose sum is σ = 253243314098. Its totient is φ = 253243314096.

The previous prime is 253243314091. The next prime is 253243314151. The reversal of 253243314097 is 790413342352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 152249016481 + 100994297616 = 390191^2 + 317796^2 .

It is a cyclic number.

It is not a de Polignac number, because 253243314097 - 215 = 253243281329 is a prime.

It is a super-2 number, since 2×2532433140972 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (253243314091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126621657048 + 126621657049.

It is an arithmetic number, because the mean of its divisors is an integer number (126621657049).

Almost surely, 2253243314097 is an apocalyptic number.

It is an amenable number.

253243314097 is a deficient number, since it is larger than the sum of its proper divisors (1).

253243314097 is an equidigital number, since it uses as much as digits as its factorization.

253243314097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 544320, while the sum is 43.

The spelling of 253243314097 in words is "two hundred fifty-three billion, two hundred forty-three million, three hundred fourteen thousand, ninety-seven".