Base | Representation |
---|---|
bin | 1110101111011001111… |
… | …0100100111110110001 |
3 | 220012122221222021122121 |
4 | 3223312132210332301 |
5 | 13122120242022342 |
6 | 312201031034241 |
7 | 24203414436664 |
oct | 3536636447661 |
9 | 805587867577 |
10 | 253243314097 |
11 | 98444281124 |
12 | 410b680b981 |
13 | 1ab5acb4867 |
14 | c3854736db |
15 | 68c2921067 |
hex | 3af67a4fb1 |
253243314097 has 2 divisors, whose sum is σ = 253243314098. Its totient is φ = 253243314096.
The previous prime is 253243314091. The next prime is 253243314151. The reversal of 253243314097 is 790413342352.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 152249016481 + 100994297616 = 390191^2 + 317796^2 .
It is a cyclic number.
It is not a de Polignac number, because 253243314097 - 215 = 253243281329 is a prime.
It is a super-2 number, since 2×2532433140972 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (253243314091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126621657048 + 126621657049.
It is an arithmetic number, because the mean of its divisors is an integer number (126621657049).
Almost surely, 2253243314097 is an apocalyptic number.
It is an amenable number.
253243314097 is a deficient number, since it is larger than the sum of its proper divisors (1).
253243314097 is an equidigital number, since it uses as much as digits as its factorization.
253243314097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 43.
The spelling of 253243314097 in words is "two hundred fifty-three billion, two hundred forty-three million, three hundred fourteen thousand, ninety-seven".
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