253313305433 has 2 divisors, whose sum is σ = 253313305434. Its totient is φ = 253313305432.

The previous prime is 253313305403. The next prime is 253313305447. The reversal of 253313305433 is 334503313352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132982020889 + 120331284544 = 364667^2 + 346888^2 .

It is a cyclic number.

It is not a de Polignac number, because 253313305433 - 2²² = 253309111129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 253313305393 and 253313305402.

It is not a weakly prime, because it can be changed into another prime (253313305403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126656652716 + 126656652717.

It is an arithmetic number, because the mean of its divisors is an integer number (126656652717).

Almost surely, 2^253313305433 is an apocalyptic number.

It is an amenable number.

253313305433 is a deficient number, since it is larger than the sum of its proper divisors (1).

253313305433 is an equidigital number, since it uses as much as digits as its factorization.

253313305433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145800, while the sum is 35.

Adding to 253313305433 its reverse (334503313352), we get a palindrome (587816618785).

The spelling of 253313305433 in words is "two hundred fifty-three billion, three hundred thirteen million, three hundred five thousand, four hundred thirty-three".