Base | Representation |
---|---|
bin | 111001100110110010010100… |
… | …000000111100010101011001 |
3 | 1020020001101222212002210211001 |
4 | 321212302110000330111121 |
5 | 231201423010104202140 |
6 | 2254501121033505001 |
7 | 104236136436542515 |
oct | 7146622400742531 |
9 | 1206041885083731 |
10 | 253354014131545 |
11 | 737a991a062948 |
12 | 244b9856872161 |
13 | ab4a24790c022 |
14 | 467c584b49145 |
15 | 1e454bcaade9a |
hex | e66c9403c559 |
253354014131545 has 16 divisors (see below), whose sum is σ = 307072177326720. Its totient is φ = 200652864177024.
The previous prime is 253354014131521. The next prime is 253354014131593. The reversal of 253354014131545 is 545131410453352.
It is a cyclic number.
It is not a de Polignac number, because 253354014131545 - 215 = 253354014098777 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 253354014131495 and 253354014131504.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 74998899 + ... + 78304168.
It is an arithmetic number, because the mean of its divisors is an integer number (19192011082920).
Almost surely, 2253354014131545 is an apocalyptic number.
It is an amenable number.
253354014131545 is a deficient number, since it is larger than the sum of its proper divisors (53718163195175).
253354014131545 is a wasteful number, since it uses less digits than its factorization.
253354014131545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153306384.
The product of its (nonzero) digits is 2160000, while the sum is 46.
Adding to 253354014131545 its reverse (545131410453352), we get a palindrome (798485424584897).
The spelling of 253354014131545 in words is "two hundred fifty-three trillion, three hundred fifty-four billion, fourteen million, one hundred thirty-one thousand, five hundred forty-five".
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