Base | Representation |
---|---|
bin | 1011100001100001010010… |
… | …10111101100110010001001 |
3 | 10022201120112221100121122021 |
4 | 11300300221113230302021 |
5 | 11310141332242000001 |
6 | 125521254544124441 |
7 | 5223553426355122 |
oct | 560605127546211 |
9 | 108646487317567 |
10 | 25341001125001 |
11 | 8090070550971 |
12 | 2a1330a006721 |
13 | 111a85279b3c3 |
14 | 638722275049 |
15 | 2de29e5a2ba1 |
hex | 170c295ecc89 |
25341001125001 has 2 divisors, whose sum is σ = 25341001125002. Its totient is φ = 25341001125000.
The previous prime is 25341001124993. The next prime is 25341001125059. The reversal of 25341001125001 is 10052110014352.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16666798085001 + 8674203040000 = 4082499^2 + 2945200^2 .
It is a cyclic number.
It is not a de Polignac number, because 25341001125001 - 23 = 25341001124993 is a prime.
It is not a weakly prime, because it can be changed into another prime (25341001122001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12670500562500 + 12670500562501.
It is an arithmetic number, because the mean of its divisors is an integer number (12670500562501).
Almost surely, 225341001125001 is an apocalyptic number.
It is an amenable number.
25341001125001 is a deficient number, since it is larger than the sum of its proper divisors (1).
25341001125001 is an equidigital number, since it uses as much as digits as its factorization.
25341001125001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 25341001125001 its reverse (10052110014352), we get a palindrome (35393111139353).
The spelling of 25341001125001 in words is "twenty-five trillion, three hundred forty-one billion, one million, one hundred twenty-five thousand, one".
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