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2534540430001 = 13003194919667
BaseRepresentation
bin100100111000011110011…
…000011100101010110001
322222022002110222012121211
4210320132120130222301
5313011214322230001
65220203553320121
7351054163122466
oct44703630345261
98868073865554
102534540430001
1189798aaa75a8
1234b264566041
131550106381b8
148a95b14d66d
1545de1162351
hex24e1e61cab1

2534540430001 has 4 divisors (see below), whose sum is σ = 2534735362672. Its totient is φ = 2534345497332.

The previous prime is 2534540429989. The next prime is 2534540430017. The reversal of 2534540430001 is 1000340454352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2534540430001 - 27 = 2534540429873 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2534540430601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97446831 + ... + 97472836.

It is an arithmetic number, because the mean of its divisors is an integer number (633683840668).

Almost surely, 22534540430001 is an apocalyptic number.

It is an amenable number.

2534540430001 is a deficient number, since it is larger than the sum of its proper divisors (194932671).

2534540430001 is a wasteful number, since it uses less digits than its factorization.

2534540430001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 194932670.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 2534540430001 its reverse (1000340454352), we get a palindrome (3534880884353).

The spelling of 2534540430001 in words is "two trillion, five hundred thirty-four billion, five hundred forty million, four hundred thirty thousand, one".

Divisors: 1 13003 194919667 2534540430001