Base | Representation |
---|---|
bin | 111001101000101010101111… |
… | …001110001100111010000011 |
3 | 1020020111202202101011202101010 |
4 | 321220222233032030322003 |
5 | 231211032314310023021 |
6 | 2255040343543012003 |
7 | 104251364651146620 |
oct | 7150525716147203 |
9 | 1206452671152333 |
10 | 253483319611011 |
11 | 73849743695466 |
12 | 2451a922a3a003 |
13 | ab594b3942559 |
14 | 468492dca5347 |
15 | 1e48a39983976 |
hex | e68aaf38ce83 |
253483319611011 has 8 divisors (see below), whose sum is σ = 386260296550144. Its totient is φ = 144847611206280.
The previous prime is 253483319611007. The next prime is 253483319611019. The reversal of 253483319611011 is 110116913384352.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 253483319611011 - 22 = 253483319611007 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (253483319611019) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6035317133575 + ... + 6035317133616.
It is an arithmetic number, because the mean of its divisors is an integer number (48282537068768).
Almost surely, 2253483319611011 is an apocalyptic number.
253483319611011 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
253483319611011 is a deficient number, since it is larger than the sum of its proper divisors (132776976939133).
253483319611011 is a wasteful number, since it uses less digits than its factorization.
253483319611011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12070634267201.
The product of its (nonzero) digits is 466560, while the sum is 48.
The spelling of 253483319611011 in words is "two hundred fifty-three trillion, four hundred eighty-three billion, three hundred nineteen million, six hundred eleven thousand, eleven".
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