Base | Representation |
---|---|
bin | 1011100001110100010011… |
… | …00010101001011010100001 |
3 | 10022202112220000212220120202 |
4 | 11300322021202221122201 |
5 | 11310323231330321423 |
6 | 125530103234514545 |
7 | 5224364324105642 |
oct | 560721142513241 |
9 | 108675800786522 |
10 | 25351204542113 |
11 | 809442707219a |
12 | 2a15297135a55 |
13 | 111b7ba66b318 |
14 | 63900d4296c9 |
15 | 2de69a242728 |
hex | 170e898a96a1 |
25351204542113 has 8 divisors (see below), whose sum is σ = 25776095618880. Its totient is φ = 24928197683760.
The previous prime is 25351204542091. The next prime is 25351204542121. The reversal of 25351204542113 is 31124540215352.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 25351204542113 - 212 = 25351204538017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25351204532113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 471027470 + ... + 471081287.
It is an arithmetic number, because the mean of its divisors is an integer number (3222011952360).
Almost surely, 225351204542113 is an apocalyptic number.
It is an amenable number.
25351204542113 is a deficient number, since it is larger than the sum of its proper divisors (424891076767).
25351204542113 is an equidigital number, since it uses as much as digits as its factorization.
25351204542113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 942109207.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 25351204542113 its reverse (31124540215352), we get a palindrome (56475744757465).
The spelling of 25351204542113 in words is "twenty-five trillion, three hundred fifty-one billion, two hundred four million, five hundred forty-two thousand, one hundred thirteen".
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