Base | Representation |
---|---|
bin | 100100111101000000110… |
… | …100100011110011001001 |
3 | 22222202200001221011022001 |
4 | 210331000310203303021 |
5 | 313101204234120011 |
6 | 5222331301431001 |
7 | 351316011661366 |
oct | 44750064436311 |
9 | 8882601834261 |
10 | 2539413191881 |
11 | 899a605a9735 |
12 | 3501a440b461 |
13 | 155609007457 |
14 | 8aca036d46d |
15 | 460c8d337c1 |
hex | 24f40d23cc9 |
2539413191881 has 2 divisors, whose sum is σ = 2539413191882. Its totient is φ = 2539413191880.
The previous prime is 2539413191869. The next prime is 2539413191923. The reversal of 2539413191881 is 1881913149352.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2266051526281 + 273361665600 = 1505341^2 + 522840^2 .
It is a cyclic number.
It is not a de Polignac number, because 2539413191881 - 25 = 2539413191849 is a prime.
It is a super-2 number, since 2×25394131918812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2539413101881) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1269706595940 + 1269706595941.
It is an arithmetic number, because the mean of its divisors is an integer number (1269706595941).
Almost surely, 22539413191881 is an apocalyptic number.
It is an amenable number.
2539413191881 is a deficient number, since it is larger than the sum of its proper divisors (1).
2539413191881 is an equidigital number, since it uses as much as digits as its factorization.
2539413191881 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1866240, while the sum is 55.
The spelling of 2539413191881 in words is "two trillion, five hundred thirty-nine billion, four hundred thirteen million, one hundred ninety-one thousand, eight hundred eighty-one".
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