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253968967257 = 384656322419
BaseRepresentation
bin1110110010000110111…
…0101110011001011001
3220021112112102021122120
43230201232232121121
513130112023423012
6312401032211453
724230405413605
oct3544156563131
9807475367576
10253968967257
1198786952085
1241279839b89
131ac45436525
14c4139a8505
1569164ae58c
hex3b21bae659

253968967257 has 4 divisors (see below), whose sum is σ = 338625289680. Its totient is φ = 169312644836.

The previous prime is 253968967249. The next prime is 253968967283. The reversal of 253968967257 is 752769869352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 253968967257 - 23 = 253968967249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 253968967191 and 253968967200.

It is not an unprimeable number, because it can be changed into a prime (253968967247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42328161207 + ... + 42328161212.

It is an arithmetic number, because the mean of its divisors is an integer number (84656322420).

Almost surely, 2253968967257 is an apocalyptic number.

It is an amenable number.

253968967257 is a deficient number, since it is larger than the sum of its proper divisors (84656322423).

253968967257 is an equidigital number, since it uses as much as digits as its factorization.

253968967257 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84656322422.

The product of its digits is 342921600, while the sum is 69.

The spelling of 253968967257 in words is "two hundred fifty-three billion, nine hundred sixty-eight million, nine hundred sixty-seven thousand, two hundred fifty-seven".

Divisors: 1 3 84656322419 253968967257