25398483628058 has 4 divisors (see below), whose sum is σ = 38097725442090. Its totient is φ = 12699241814028.

The previous prime is 25398483628043. The next prime is 25398483628093. The reversal of 25398483628058 is 85082638489352.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 16076435068849 + 9322048559209 = 4009543^2 + 3053203^2 .

It is a super-3 number, since 3×25398483628058³ (a number of 41 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 25398483627982 and 25398483628000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6349620907013 + ... + 6349620907016.

Almost surely, 2^{25398483628058} is an apocalyptic number.

25398483628058 is a deficient number, since it is larger than the sum of its proper divisors (12699241814032).

25398483628058 is a wasteful number, since it uses less digits than its factorization.

25398483628058 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12699241814031.

The product of its (nonzero) digits is 796262400, while the sum is 71.

The spelling of 25398483628058 in words is "twenty-five trillion, three hundred ninety-eight billion, four hundred eighty-three million, six hundred twenty-eight thousand, fifty-eight".