254004212113 has 4 divisors (see below), whose sum is σ = 254503238580. Its totient is φ = 253505185648.

The previous prime is 254004212069. The next prime is 254004212129. The reversal of 254004212113 is 311212400452.

254004212113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 88361724049 + 165642488064 = 297257^2 + 406992^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-254004212113 is a prime.

It is a super-3 number, since 3×254004212113³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (254004216113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 249512470 + ... + 249513487.

It is an arithmetic number, because the mean of its divisors is an integer number (63625809645).

Almost surely, 2^254004212113 is an apocalyptic number.

It is an amenable number.

254004212113 is a deficient number, since it is larger than the sum of its proper divisors (499026467).

254004212113 is an equidigital number, since it uses as much as digits as its factorization.

254004212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 499026466.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 254004212113 its reverse (311212400452), we get a palindrome (565216612565).

The spelling of 254004212113 in words is "two hundred fifty-four billion, four million, two hundred twelve thousand, one hundred thirteen".