Base | Representation |
---|---|
bin | 100100111101110010011… |
… | …011100111000000000001 |
3 | 22222211211002002102010021 |
4 | 210331302123213000001 |
5 | 313104410322342233 |
6 | 5222550033133441 |
7 | 351345436406254 |
oct | 44756233470001 |
9 | 8884732072107 |
10 | 2540245512193 |
11 | 89a348405264 |
12 | 3503970ba281 |
13 | 15570c59548c |
14 | 8ad3cb0d09b |
15 | 46126e41e2d |
hex | 24f726e7001 |
2540245512193 has 2 divisors, whose sum is σ = 2540245512194. Its totient is φ = 2540245512192.
The previous prime is 2540245512169. The next prime is 2540245512257. The reversal of 2540245512193 is 3912155420452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2535154975089 + 5090537104 = 1592217^2 + 71348^2 .
It is a cyclic number.
It is not a de Polignac number, because 2540245512193 - 29 = 2540245511681 is a prime.
It is not a weakly prime, because it can be changed into another prime (2540245512113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270122756096 + 1270122756097.
It is an arithmetic number, because the mean of its divisors is an integer number (1270122756097).
Almost surely, 22540245512193 is an apocalyptic number.
It is an amenable number.
2540245512193 is a deficient number, since it is larger than the sum of its proper divisors (1).
2540245512193 is an equidigital number, since it uses as much as digits as its factorization.
2540245512193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432000, while the sum is 43.
The spelling of 2540245512193 in words is "two trillion, five hundred forty billion, two hundred forty-five million, five hundred twelve thousand, one hundred ninety-three".
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