2540255310433 has 2 divisors, whose sum is σ = 2540255310434. Its totient is φ = 2540255310432.

The previous prime is 2540255310413. The next prime is 2540255310563. The reversal of 2540255310433 is 3340135520452.

2540255310433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1879388744464 + 660866565969 = 1370908^2 + 812937^2 .

It is a cyclic number.

It is not a de Polignac number, because 2540255310433 - 2¹³ = 2540255302241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2540255310392 and 2540255310401.

It is not a weakly prime, because it can be changed into another prime (2540255310413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270127655216 + 1270127655217.

It is an arithmetic number, because the mean of its divisors is an integer number (1270127655217).

Almost surely, 2^{2540255310433} is an apocalyptic number.

It is an amenable number.

2540255310433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2540255310433 is an equidigital number, since it uses as much as digits as its factorization.

2540255310433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 37.

The spelling of 2540255310433 in words is "two trillion, five hundred forty billion, two hundred fifty-five million, three hundred ten thousand, four hundred thirty-three".