Base | Representation |
---|---|
bin | 100100111101110110111… |
… | …111011100011111011001 |
3 | 22222212000102001011111201 |
4 | 210331312333130133121 |
5 | 313110034413441233 |
6 | 5223001404554201 |
7 | 351350355566134 |
oct | 44756677343731 |
9 | 8885012034451 |
10 | 2540322015193 |
11 | 89a387608086 |
12 | 3503b8852961 |
13 | 15572239cc21 |
14 | 8ad48d4521b |
15 | 4612da0477d |
hex | 24f76fdc7d9 |
2540322015193 has 2 divisors, whose sum is σ = 2540322015194. Its totient is φ = 2540322015192.
The previous prime is 2540322015113. The next prime is 2540322015271. The reversal of 2540322015193 is 3915102230452.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2532035190169 + 8286825024 = 1591237^2 + 91032^2 .
It is a cyclic number.
It is not a de Polignac number, because 2540322015193 - 221 = 2540319918041 is a prime.
It is not a weakly prime, because it can be changed into another prime (2540322015113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270161007596 + 1270161007597.
It is an arithmetic number, because the mean of its divisors is an integer number (1270161007597).
Almost surely, 22540322015193 is an apocalyptic number.
It is an amenable number.
2540322015193 is a deficient number, since it is larger than the sum of its proper divisors (1).
2540322015193 is an equidigital number, since it uses as much as digits as its factorization.
2540322015193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 2540322015193 in words is "two trillion, five hundred forty billion, three hundred twenty-two million, fifteen thousand, one hundred ninety-three".
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