Base | Representation |
---|---|
bin | 1001011101110001… |
… | …1000111110110011 |
3 | 20120001222010001201 |
4 | 2113130120332303 |
5 | 20200421130341 |
6 | 1100042112031 |
7 | 116651313631 |
oct | 22734307663 |
9 | 6501863051 |
10 | 2540801971 |
11 | 1094242144 |
12 | 5aaaab617 |
13 | 316517026 |
14 | 1a1632351 |
15 | ed0da331 |
hex | 97718fb3 |
2540801971 has 2 divisors, whose sum is σ = 2540801972. Its totient is φ = 2540801970.
The previous prime is 2540801957. The next prime is 2540801983. The reversal of 2540801971 is 1791080452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2540801971 - 27 = 2540801843 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2540801971.
It is not a weakly prime, because it can be changed into another prime (2540801941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270400985 + 1270400986.
It is an arithmetic number, because the mean of its divisors is an integer number (1270400986).
Almost surely, 22540801971 is an apocalyptic number.
2540801971 is a deficient number, since it is larger than the sum of its proper divisors (1).
2540801971 is an equidigital number, since it uses as much as digits as its factorization.
2540801971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 37.
The square root of 2540801971 is about 50406.3683575796. The cubic root of 2540801971 is about 1364.5525726105.
The spelling of 2540801971 in words is "two billion, five hundred forty million, eight hundred one thousand, nine hundred seventy-one".
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