254113521011131 has 2 divisors, whose sum is σ = 254113521011132. Its totient is φ = 254113521011130.

The previous prime is 254113521011087. The next prime is 254113521011183. The reversal of 254113521011131 is 131110125311452.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 254113521011131 - 2¹¹ = 254113521009083 is a prime.

It is a super-2 number, since 2×254113521011131² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 254113521011093 and 254113521011102.

It is not a weakly prime, because it can be changed into another prime (254113521021131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127056760505565 + 127056760505566.

It is an arithmetic number, because the mean of its divisors is an integer number (127056760505566).

Almost surely, 2^{254113521011131} is an apocalyptic number.

254113521011131 is a deficient number, since it is larger than the sum of its proper divisors (1).

254113521011131 is an equidigital number, since it uses as much as digits as its factorization.

254113521011131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 31.

Adding to 254113521011131 its reverse (131110125311452), we get a palindrome (385223646322583).

The spelling of 254113521011131 in words is "two hundred fifty-four trillion, one hundred thirteen billion, five hundred twenty-one million, eleven thousand, one hundred thirty-one".