Base | Representation |
---|---|
bin | 1110110010101001110… |
… | …1100000110010110001 |
3 | 220021220202001101020120 |
4 | 3230222131200302301 |
5 | 13130412023400113 |
6 | 312423344000453 |
7 | 24234134454234 |
oct | 3545235406261 |
9 | 807822041216 |
10 | 254115450033 |
11 | 98851601825 |
12 | 412ba900129 |
13 | 1ac698a3523 |
14 | c42921941b |
15 | 6924296a23 |
hex | 3b2a760cb1 |
254115450033 has 32 divisors (see below), whose sum is σ = 361101534336. Its totient is φ = 158401225728.
The previous prime is 254115450007. The next prime is 254115450089. The reversal of 254115450033 is 330054511452.
254115450033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 254115450033 - 222 = 254111255729 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 254115449976 and 254115450003.
It is not an unprimeable number, because it can be changed into a prime (254115458033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27037491 + ... + 27046887.
It is an arithmetic number, because the mean of its divisors is an integer number (11284422948).
Almost surely, 2254115450033 is an apocalyptic number.
It is an amenable number.
254115450033 is a deficient number, since it is larger than the sum of its proper divisors (106986084303).
254115450033 is a wasteful number, since it uses less digits than its factorization.
254115450033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12833.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 254115450033 its reverse (330054511452), we get a palindrome (584169961485).
The spelling of 254115450033 in words is "two hundred fifty-four billion, one hundred fifteen million, four hundred fifty thousand, thirty-three".
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