Base | Representation |
---|---|
bin | 1011100011100101101000… |
… | …11101111000001101001011 |
3 | 10022222100221202100120110211 |
4 | 11301302310131320031023 |
5 | 11312322341342120121 |
6 | 130014045255221551 |
7 | 5231650252115656 |
oct | 561626435701513 |
9 | 108870852316424 |
10 | 25412054254411 |
11 | 8108212154720 |
12 | 2a250396778b7 |
13 | 1124467165846 |
14 | 63bd42aa889d |
15 | 2e105c38bce1 |
hex | 171cb477834b |
25412054254411 has 16 divisors (see below), whose sum is σ = 28776208347648. Its totient is φ = 22239677095200.
The previous prime is 25412054254397. The next prime is 25412054254441. The reversal of 25412054254411 is 11445245021452.
It is a cyclic number.
It is not a de Polignac number, because 25412054254411 - 215 = 25412054221643 is a prime.
It is a super-2 number, since 2×254120542544112 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25412054254441) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 402861165 + ... + 402924238.
It is an arithmetic number, because the mean of its divisors is an integer number (1798513021728).
Almost surely, 225412054254411 is an apocalyptic number.
25412054254411 is a deficient number, since it is larger than the sum of its proper divisors (3364154093237).
25412054254411 is a wasteful number, since it uses less digits than its factorization.
25412054254411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 805785522.
The product of its (nonzero) digits is 256000, while the sum is 40.
Adding to 25412054254411 its reverse (11445245021452), we get a palindrome (36857299275863).
The spelling of 25412054254411 in words is "twenty-five trillion, four hundred twelve billion, fifty-four million, two hundred fifty-four thousand, four hundred eleven".
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