254121422100131 has 4 divisors (see below), whose sum is σ = 254129477459352. Its totient is φ = 254113366740912.

The previous prime is 254121422100109. The next prime is 254121422100167. The reversal of 254121422100131 is 131001224121452.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 254121422100131 - 2¹⁰ = 254121422099107 is a prime.

It is a super-2 number, since 2×254121422100131² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 254121422100094 and 254121422100103.

It is not an unprimeable number, because it can be changed into a prime (254121422100331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4027632290 + ... + 4027695383.

It is an arithmetic number, because the mean of its divisors is an integer number (63532369364838).

Almost surely, 2^{254121422100131} is an apocalyptic number.

254121422100131 is a deficient number, since it is larger than the sum of its proper divisors (8055359221).

254121422100131 is an equidigital number, since it uses as much as digits as its factorization.

254121422100131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8055359220.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 254121422100131 its reverse (131001224121452), we get a palindrome (385122646221583).

The spelling of 254121422100131 in words is "two hundred fifty-four trillion, one hundred twenty-one billion, four hundred twenty-two million, one hundred thousand, one hundred thirty-one".