Base | Representation |
---|---|
bin | 1110110010101101101… |
… | …0001110000100101110 |
3 | 220021221211222220022000 |
4 | 3230223122032010232 |
5 | 13130430112123032 |
6 | 312425113033130 |
7 | 24234416645115 |
oct | 3545332160456 |
9 | 807854886260 |
10 | 254131364142 |
11 | 9885a591287 |
12 | 413040b57a6 |
13 | 1ac6cc85c66 |
14 | c42b39cc7c |
15 | 692588be7c |
hex | 3b2b68e12e |
254131364142 has 32 divisors (see below), whose sum is σ = 564790288800. Its totient is φ = 84702366144.
The previous prime is 254131364131. The next prime is 254131364153. The reversal of 254131364142 is 241463131452.
254131364142 is a `hidden beast` number, since 2 + 5 + 4 + 1 + 3 + 1 + 3 + 641 + 4 + 2 = 666.
It is an interprime number because it is at equal distance from previous prime (254131364131) and next prime (254131364153).
It is a junction number, because it is equal to n+sod(n) for n = 254131364097 and 254131364106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 360048 + ... + 798684.
It is an arithmetic number, because the mean of its divisors is an integer number (17649696525).
Almost surely, 2254131364142 is an apocalyptic number.
254131364142 is an abundant number, since it is smaller than the sum of its proper divisors (310658924658).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
254131364142 is a wasteful number, since it uses less digits than its factorization.
254131364142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 449377 (or 449371 counting only the distinct ones).
The product of its digits is 69120, while the sum is 36.
Adding to 254131364142 its reverse (241463131452), we get a palindrome (495594495594).
The spelling of 254131364142 in words is "two hundred fifty-four billion, one hundred thirty-one million, three hundred sixty-four thousand, one hundred forty-two".
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