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254244254113 = 2243113350091
BaseRepresentation
bin1110110011001000100…
…0110111000110100001
3220022020201102022020001
43230302020313012201
513131143012112423
6312444224420001
724240260334313
oct3546210670641
9808221368201
10254244254113
1198908287183
1241335a77601
131ac8a490865
14c43c3877b3
15693073acad
hex3b322371a1

254244254113 has 4 divisors (see below), whose sum is σ = 254357606448. Its totient is φ = 254130901780.

The previous prime is 254244254107. The next prime is 254244254119. The reversal of 254244254113 is 311452442452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (254244254107) and next prime (254244254119).

It is a cyclic number.

It is not a de Polignac number, because 254244254113 - 217 = 254244123041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (254244254119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56672803 + ... + 56677288.

It is an arithmetic number, because the mean of its divisors is an integer number (63589401612).

Almost surely, 2254244254113 is an apocalyptic number.

It is an amenable number.

254244254113 is a deficient number, since it is larger than the sum of its proper divisors (113352335).

254244254113 is a wasteful number, since it uses less digits than its factorization.

254244254113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113352334.

The product of its digits is 153600, while the sum is 37.

Adding to 254244254113 its reverse (311452442452), we get a palindrome (565696696565).

The spelling of 254244254113 in words is "two hundred fifty-four billion, two hundred forty-four million, two hundred fifty-four thousand, one hundred thirteen".

Divisors: 1 2243 113350091 254244254113