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25424510057 is a prime number
BaseRepresentation
bin10111101011011010…
…110011110001101001
32102121212200221010122
4113223122303301221
5404032133310212
615402503253025
71560020525012
oct275332636151
972555627118
1025424510057
11a867522791
124b1674a175
132522479cbb
1413328cc009
159dc0c8272
hex5eb6b3c69

25424510057 has 2 divisors, whose sum is σ = 25424510058. Its totient is φ = 25424510056.

The previous prime is 25424509997. The next prime is 25424510093. The reversal of 25424510057 is 75001542452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25375215616 + 49294441 = 159296^2 + 7021^2 .

It is a cyclic number.

It is not a de Polignac number, because 25424510057 - 218 = 25424247913 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25424509999 and 25424510026.

It is not a weakly prime, because it can be changed into another prime (25424510957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12712255028 + 12712255029.

It is an arithmetic number, because the mean of its divisors is an integer number (12712255029).

Almost surely, 225424510057 is an apocalyptic number.

It is an amenable number.

25424510057 is a deficient number, since it is larger than the sum of its proper divisors (1).

25424510057 is an equidigital number, since it uses as much as digits as its factorization.

25424510057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56000, while the sum is 35.

The spelling of 25424510057 in words is "twenty-five billion, four hundred twenty-four million, five hundred ten thousand, fifty-seven".