Base | Representation |
---|---|
bin | 100101000000011110111… |
… | …100101000110010101001 |
3 | 100000010021210022002010220 |
4 | 211000132330220302221 |
5 | 313131322300221213 |
6 | 5224145145000253 |
7 | 351510243032136 |
oct | 45003674506251 |
9 | 10003253262126 |
10 | 2543139851433 |
11 | 8a05a3168165 |
12 | 350a64483089 |
13 | 155a8110374c |
14 | 8b13528d58d |
15 | 462460b3e23 |
hex | 2501ef28ca9 |
2543139851433 has 16 divisors (see below), whose sum is σ = 3616521773760. Its totient is φ = 1584048175616.
The previous prime is 2543139851383. The next prime is 2543139851443. The reversal of 2543139851433 is 3341589313452.
It is not a de Polignac number, because 2543139851433 - 217 = 2543139720361 is a prime.
It is a super-2 number, since 2×25431398514332 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is not an unprimeable number, because it can be changed into a prime (2543139851443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 181983843 + ... + 181997816.
It is an arithmetic number, because the mean of its divisors is an integer number (226032610860).
Almost surely, 22543139851433 is an apocalyptic number.
It is an amenable number.
2543139851433 is a deficient number, since it is larger than the sum of its proper divisors (1073381922327).
2543139851433 is a wasteful number, since it uses less digits than its factorization.
2543139851433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 363981816.
The product of its digits is 4665600, while the sum is 51.
The spelling of 2543139851433 in words is "two trillion, five hundred forty-three billion, one hundred thirty-nine million, eight hundred fifty-one thousand, four hundred thirty-three".
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