2543313052041 has 8 divisors (see below), whose sum is σ = 3391091747904. Its totient is φ = 1695538195440.

The previous prime is 2543313051971. The next prime is 2543313052069. The reversal of 2543313052041 is 1402503133452.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2543313052041 - 2⁹ = 2543313051529 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2543313051993 and 2543313052011.

It is not an unprimeable number, because it can be changed into a prime (2543313056041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1450836 + ... + 2681706.

It is an arithmetic number, because the mean of its divisors is an integer number (423886468488).

Almost surely, 2^{2543313052041} is an apocalyptic number.

It is an amenable number.

2543313052041 is a deficient number, since it is larger than the sum of its proper divisors (847778695863).

2543313052041 is a wasteful number, since it uses less digits than its factorization.

2543313052041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1919631.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 2543313052041 its reverse (1402503133452), we get a palindrome (3945816185493).

The spelling of 2543313052041 in words is "two trillion, five hundred forty-three billion, three hundred thirteen million, fifty-two thousand, forty-one".