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254334341213 = 29118115794703
BaseRepresentation
bin1110110011011110000…
…0100001000001011101
3220022110222221012111022
43230313200201001131
513131334042404323
6312501203333525
724242433142031
oct3546740410135
9808428835438
10254334341213
1198954117a27
12413600812a5
131aca3043334
14c44a3181c1
1569385d34c8
hex3b3782105d

254334341213 has 16 divisors (see below), whose sum is σ = 263550067200. Its totient is φ = 245148738240.

The previous prime is 254334341207. The next prime is 254334341231. The reversal of 254334341213 is 312143433452.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-254334341213 is a prime.

It is a super-2 number, since 2×2543343412132 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (254334341263) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 54076820 + ... + 54081522.

It is an arithmetic number, because the mean of its divisors is an integer number (16471879200).

Almost surely, 2254334341213 is an apocalyptic number.

It is an amenable number.

254334341213 is a deficient number, since it is larger than the sum of its proper divisors (9215725987).

254334341213 is a wasteful number, since it uses less digits than its factorization.

254334341213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7492.

The product of its digits is 103680, while the sum is 35.

Adding to 254334341213 its reverse (312143433452), we get a palindrome (566477774665).

The spelling of 254334341213 in words is "two hundred fifty-four billion, three hundred thirty-four million, three hundred forty-one thousand, two hundred thirteen".

Divisors: 1 29 1181 1579 4703 34249 45791 136387 1864799 5554243 7426037 54079171 161073047 215355073 8770149697 254334341213