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254344214020147 is a prime number
BaseRepresentation
bin111001110101001100100000…
…100001110000000000110011
31020100120001212120212222210021
4321311030200201300000303
5231314133422242121042
62300540041401544311
7104400522504661306
oct7165144041600063
91210501776788707
10254344214020147
1174050859090019
12246397427a5097
13abbc730735a84
1446b447b7c2b3d
151e61123c9d867
hexe75320870033

254344214020147 has 2 divisors, whose sum is σ = 254344214020148. Its totient is φ = 254344214020146.

The previous prime is 254344214020111. The next prime is 254344214020151. The reversal of 254344214020147 is 741020412443452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 254344214020147 - 211 = 254344214018099 is a prime.

It is not a weakly prime, because it can be changed into another prime (254344214020447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127172107010073 + 127172107010074.

It is an arithmetic number, because the mean of its divisors is an integer number (127172107010074).

Almost surely, 2254344214020147 is an apocalyptic number.

254344214020147 is a deficient number, since it is larger than the sum of its proper divisors (1).

254344214020147 is an equidigital number, since it uses as much as digits as its factorization.

254344214020147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 860160, while the sum is 43.

Adding to 254344214020147 its reverse (741020412443452), we get a palindrome (995364626463599).

The spelling of 254344214020147 in words is "two hundred fifty-four trillion, three hundred forty-four billion, two hundred fourteen million, twenty thousand, one hundred forty-seven".