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25442413000001 is a prime number
BaseRepresentation
bin1011100100011110001011…
…11111010011010101000001
310100002021022111200122021122
411302033011333103111001
511313322030212000001
6130040025544402025
75234103466155224
oct562170577232501
9110067274618248
1025442413000001
11811a080946608
122a2aab0776315
13112729495672a
1463d5c2a195bb
152e1c3772ab1b
hex1723c5fd3541

25442413000001 has 2 divisors, whose sum is σ = 25442413000002. Its totient is φ = 25442413000000.

The previous prime is 25442412999989. The next prime is 25442413000007. The reversal of 25442413000001 is 10000031424452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23192940969025 + 2249472030976 = 4815905^2 + 1499824^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25442413000001 is a prime.

It is not a weakly prime, because it can be changed into another prime (25442413000007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12721206500000 + 12721206500001.

It is an arithmetic number, because the mean of its divisors is an integer number (12721206500001).

Almost surely, 225442413000001 is an apocalyptic number.

It is an amenable number.

25442413000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

25442413000001 is an equidigital number, since it uses as much as digits as its factorization.

25442413000001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 25442413000001 its reverse (10000031424452), we get a palindrome (35442444424453).

The spelling of 25442413000001 in words is "twenty-five trillion, four hundred forty-two billion, four hundred thirteen million, one", and thus it is an aban number.