Search a number
-
+
254430136513 = 736347162359
BaseRepresentation
bin1110110011110100110…
…1111100100011000001
3220022201200012002221101
43230331031330203001
513132033103332023
6312514504454401
724245005322440
oct3547515744301
9808650162841
10254430136513
11989a31a73a3
124138817a401
131acb9b44047
14c458d32d57
156941c071ad
hex3b3d37c8c1

254430136513 has 4 divisors (see below), whose sum is σ = 290777298880. Its totient is φ = 218082974148.

The previous prime is 254430136511. The next prime is 254430136553. The reversal of 254430136513 is 315631034452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 254430136513 - 21 = 254430136511 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (254430136511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18173581173 + ... + 18173581186.

It is an arithmetic number, because the mean of its divisors is an integer number (72694324720).

Almost surely, 2254430136513 is an apocalyptic number.

It is an amenable number.

254430136513 is a deficient number, since it is larger than the sum of its proper divisors (36347162367).

254430136513 is an equidigital number, since it uses as much as digits as its factorization.

254430136513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36347162366.

The product of its (nonzero) digits is 129600, while the sum is 37.

The spelling of 254430136513 in words is "two hundred fifty-four billion, four hundred thirty million, one hundred thirty-six thousand, five hundred thirteen".

Divisors: 1 7 36347162359 254430136513