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254505320513 is a prime number
BaseRepresentation
bin1110110100000110110…
…0110000000001000001
3220022220220122211222222
43231001230300001001
513132211330224023
6312530152140425
724246610346663
oct3550154600101
9808826584888
10254505320513
1198a31689234
12413a9397715
131accc5a9312
14c464d04533
156948608cc8
hex3b41b30041

254505320513 has 2 divisors, whose sum is σ = 254505320514. Its totient is φ = 254505320512.

The previous prime is 254505320501. The next prime is 254505320539. The reversal of 254505320513 is 315023505452.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 203480383744 + 51024936769 = 451088^2 + 225887^2 .

It is a cyclic number.

It is not a de Polignac number, because 254505320513 - 24 = 254505320497 is a prime.

It is a super-4 number, since 4×2545053205134 (a number of 47 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (254505325513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127252660256 + 127252660257.

It is an arithmetic number, because the mean of its divisors is an integer number (127252660257).

Almost surely, 2254505320513 is an apocalyptic number.

It is an amenable number.

254505320513 is a deficient number, since it is larger than the sum of its proper divisors (1).

254505320513 is an equidigital number, since it uses as much as digits as its factorization.

254505320513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90000, while the sum is 35.

Adding to 254505320513 its reverse (315023505452), we get a palindrome (569528825965).

The spelling of 254505320513 in words is "two hundred fifty-four billion, five hundred five million, three hundred twenty thousand, five hundred thirteen".