Base | Representation |
---|---|
bin | 10111101110001111… |
… | …111110000110010001 |
3 | 2102202012001200122021 |
4 | 113232033332012101 |
5 | 404131313003101 |
6 | 15411321211441 |
7 | 1561135300561 |
oct | 275617760621 |
9 | 72665050567 |
10 | 25472000401 |
11 | a891309a01 |
12 | 4b2a630b81 |
13 | 252c266cb3 |
14 | 1338d30da1 |
15 | 9e13595a1 |
hex | 5ee3fe191 |
25472000401 has 4 divisors (see below), whose sum is σ = 25512368704. Its totient is φ = 25431632100.
The previous prime is 25472000369. The next prime is 25472000413. The reversal of 25472000401 is 10400027452.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25472000401 - 25 = 25472000369 is a prime.
It is the 159600-th Hogben number.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25472000101) by changing a digit.
It is a nontrivial repunit in base 159599.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20183205 + ... + 20184466.
It is an arithmetic number, because the mean of its divisors is an integer number (6378092176).
Almost surely, 225472000401 is an apocalyptic number.
It is an amenable number.
25472000401 is a deficient number, since it is larger than the sum of its proper divisors (40368303).
25472000401 is an equidigital number, since it uses as much as digits as its factorization.
25472000401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40368302.
The product of its (nonzero) digits is 2240, while the sum is 25.
Adding to 25472000401 its reverse (10400027452), we get a palindrome (35872027853).
The spelling of 25472000401 in words is "twenty-five billion, four hundred seventy-two million, four hundred one", and thus it is an aban number.
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