Base | Representation |
---|---|
bin | 100101000110010001100… |
… | …000110001111101110001 |
3 | 100000201100001202200010222 |
4 | 211012101200301331301 |
5 | 313232040331133423 |
6 | 5231054113502425 |
7 | 352120304034626 |
oct | 45062140617561 |
9 | 10021301680128 |
10 | 2549356896113 |
11 | 8a31a3562915 |
12 | 3520ba571a15 |
13 | 156532143a01 |
14 | 8b564c3a34d |
15 | 464abcc13c8 |
hex | 25191831f71 |
2549356896113 has 2 divisors, whose sum is σ = 2549356896114. Its totient is φ = 2549356896112.
The previous prime is 2549356895989. The next prime is 2549356896127. The reversal of 2549356896113 is 3116986539452.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2469319959649 + 80036936464 = 1571407^2 + 282908^2 .
It is a cyclic number.
It is not a de Polignac number, because 2549356896113 - 218 = 2549356633969 is a prime.
It is not a weakly prime, because it can be changed into another prime (2549356896143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1274678448056 + 1274678448057.
It is an arithmetic number, because the mean of its divisors is an integer number (1274678448057).
Almost surely, 22549356896113 is an apocalyptic number.
It is an amenable number.
2549356896113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2549356896113 is an equidigital number, since it uses as much as digits as its factorization.
2549356896113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 41990400, while the sum is 62.
The spelling of 2549356896113 in words is "two trillion, five hundred forty-nine billion, three hundred fifty-six million, eight hundred ninety-six thousand, one hundred thirteen".
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