Base | Representation |
---|---|
bin | 1011100110001010011110… |
… | …11000000110000100110001 |
3 | 10100021211101100111221012020 |
4 | 11303011033120012010301 |
5 | 11320300112423142003 |
6 | 130122443033022053 |
7 | 5241232315206405 |
oct | 563051730060461 |
9 | 110254340457166 |
10 | 25500552552753 |
11 | 81417a6133063 |
12 | 2a3a217554929 |
13 | 112c8cbb1b155 |
14 | 64233a37d105 |
15 | 2e34db984d53 |
hex | 17314f606131 |
25500552552753 has 4 divisors (see below), whose sum is σ = 34000736737008. Its totient is φ = 17000368368500.
The previous prime is 25500552552737. The next prime is 25500552552767. The reversal of 25500552552753 is 35725525500552.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25500552552753 - 24 = 25500552552737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25500552552696 and 25500552552705.
It is not an unprimeable number, because it can be changed into a prime (25500552552793) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4250092092123 + ... + 4250092092128.
It is an arithmetic number, because the mean of its divisors is an integer number (8500184184252).
Almost surely, 225500552552753 is an apocalyptic number.
It is an amenable number.
25500552552753 is a deficient number, since it is larger than the sum of its proper divisors (8500184184255).
25500552552753 is an equidigital number, since it uses as much as digits as its factorization.
25500552552753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8500184184254.
The product of its (nonzero) digits is 13125000, while the sum is 51.
The spelling of 25500552552753 in words is "twenty-five trillion, five hundred billion, five hundred fifty-two million, five hundred fifty-two thousand, seven hundred fifty-three".
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