Base | Representation |
---|---|
bin | 1110110101111111100… |
… | …1110001010011000001 |
3 | 220101020020011101022221 |
4 | 3231133321301103001 |
5 | 13134231041100423 |
6 | 313052333131041 |
7 | 24265302442522 |
oct | 3553771612301 |
9 | 811206141287 |
10 | 255012050113 |
11 | 99171721727 |
12 | 4150b029a81 |
13 | 1b080579512 |
14 | c4b232c849 |
15 | 6977d50e5d |
hex | 3b5fe714c1 |
255012050113 has 2 divisors, whose sum is σ = 255012050114. Its totient is φ = 255012050112.
The previous prime is 255012050077. The next prime is 255012050171. The reversal of 255012050113 is 311050210552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 186790789249 + 68221260864 = 432193^2 + 261192^2 .
It is a cyclic number.
It is not a de Polignac number, because 255012050113 - 221 = 255009952961 is a prime.
It is a super-2 number, since 2×2550120501132 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (255012020113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127506025056 + 127506025057.
It is an arithmetic number, because the mean of its divisors is an integer number (127506025057).
Almost surely, 2255012050113 is an apocalyptic number.
It is an amenable number.
255012050113 is a deficient number, since it is larger than the sum of its proper divisors (1).
255012050113 is an equidigital number, since it uses as much as digits as its factorization.
255012050113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 255012050113 its reverse (311050210552), we get a palindrome (566062260665).
The spelling of 255012050113 in words is "two hundred fifty-five billion, twelve million, fifty thousand, one hundred thirteen".
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