Base | Representation |
---|---|
bin | 1001011111111111… |
… | …1110010101010011 |
3 | 20120201112000201101 |
4 | 2113333332111103 |
5 | 20210313130003 |
6 | 1101014045231 |
7 | 120123514231 |
oct | 22777762523 |
9 | 6521460641 |
10 | 2550130003 |
11 | 1099533463 |
12 | 5b2049817 |
13 | 318431a85 |
14 | 1a297d951 |
15 | edd2e11d |
hex | 97ffe553 |
2550130003 has 2 divisors, whose sum is σ = 2550130004. Its totient is φ = 2550130002.
The previous prime is 2550129983. The next prime is 2550130057. The reversal of 2550130003 is 3000310552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2550130003 - 213 = 2550121811 is a prime.
It is not a weakly prime, because it can be changed into another prime (2550130703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275065001 + 1275065002.
It is an arithmetic number, because the mean of its divisors is an integer number (1275065002).
Almost surely, 22550130003 is an apocalyptic number.
2550130003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2550130003 is an equidigital number, since it uses as much as digits as its factorization.
2550130003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 19.
The square root of 2550130003 is about 50498.8118969150. The cubic root of 2550130003 is about 1366.2204246116.
Adding to 2550130003 its reverse (3000310552), we get a palindrome (5550440555).
The spelling of 2550130003 in words is "two billion, five hundred fifty million, one hundred thirty thousand, three".
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