Base | Representation |
---|---|
bin | 10111110000000110… |
… | …011010100101001001 |
3 | 2102211100111011202112 |
4 | 113300012122211021 |
5 | 404212240100212 |
6 | 15414350512105 |
7 | 1561663230422 |
oct | 276006324511 |
9 | 72740434675 |
10 | 25503050057 |
11 | a8a7896a81 |
12 | 4b38b05635 |
13 | 2535818984 |
14 | 133d0d4649 |
15 | 9e3e3e422 |
hex | 5f019a949 |
25503050057 has 4 divisors (see below), whose sum is σ = 25510000896. Its totient is φ = 25496099220.
The previous prime is 25503050039. The next prime is 25503050059. The reversal of 25503050057 is 75005030552.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25503050057 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25503050059) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3469913 + ... + 3477254.
It is an arithmetic number, because the mean of its divisors is an integer number (6377500224).
Almost surely, 225503050057 is an apocalyptic number.
It is an amenable number.
25503050057 is a deficient number, since it is larger than the sum of its proper divisors (6950839).
25503050057 is an equidigital number, since it uses as much as digits as its factorization.
25503050057 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6950838.
The product of its (nonzero) digits is 26250, while the sum is 32.
The spelling of 25503050057 in words is "twenty-five billion, five hundred three million, fifty thousand, fifty-seven".
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