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2550345241 = 4435756987
BaseRepresentation
bin1001100000000011…
…0010111000011001
320120201220221222011
42120000302320121
520210342021431
61101022425521
7120125401603
oct23000627031
96521827864
102550345241
111099670144
125b21322a1
133184a8a32
141a29d8173
15edd72cb1
hex98032e19

2550345241 has 4 divisors (see below), whose sum is σ = 2556102672. Its totient is φ = 2544587812.

The previous prime is 2550345221. The next prime is 2550345257. The reversal of 2550345241 is 1425430552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2550345241 - 27 = 2550345113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2550345211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2878051 + ... + 2878936.

It is an arithmetic number, because the mean of its divisors is an integer number (639025668).

Almost surely, 22550345241 is an apocalyptic number.

It is an amenable number.

2550345241 is a deficient number, since it is larger than the sum of its proper divisors (5757431).

2550345241 is an equidigital number, since it uses as much as digits as its factorization.

2550345241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5757430.

The product of its (nonzero) digits is 24000, while the sum is 31.

The square root of 2550345241 is about 50500.9429713941. The cubic root of 2550345241 is about 1366.2588611199.

Adding to 2550345241 its reverse (1425430552), we get a palindrome (3975775793).

The spelling of 2550345241 in words is "two billion, five hundred fifty million, three hundred forty-five thousand, two hundred forty-one".

Divisors: 1 443 5756987 2550345241